os/security/crypto/weakcrypto/source/pkcs5kdf/pkcs5kdf.cpp
author sl
Tue, 10 Jun 2014 14:32:02 +0200
changeset 1 260cb5ec6c19
permissions -rw-r--r--
Update contrib.
     1 /*
     2 * Copyright (c) 2005-2009 Nokia Corporation and/or its subsidiary(-ies).
     3 * All rights reserved.
     4 * This component and the accompanying materials are made available
     5 * under the terms of the License "Eclipse Public License v1.0"
     6 * which accompanies this distribution, and is available
     7 * at the URL "http://www.eclipse.org/legal/epl-v10.html".
     8 *
     9 * Initial Contributors:
    10 * Nokia Corporation - initial contribution.
    11 *
    12 * Contributors:
    13 *
    14 * Description: 
    15 *
    16 */
    17 
    18 
    19 /**
    20  @file
    21 */
    22 
    23 #include "pkcs5kdf.h"
    24 
    25 /* Before complaining about the variable names in this file, 
    26  * read the pkcs5 spec and all will become clear.
    27  */
    28 
    29 EXPORT_C void TPKCS5KDF::DeriveKeyL(TDes8& aKey, const TDesC8& aPasswd, const TDesC8& aSalt, 
    30 	const TUint aIterations)
    31 {
    32 	CSHA1* sha1 = CSHA1::NewL();
    33 	CleanupStack::PushL(sha1);
    34 	CHMAC* hmac = CHMAC::NewL(aPasswd, sha1);
    35 	CleanupStack::Pop(sha1); //hmac now owns it
    36 	CleanupStack::PushL(hmac);
    37 
    38 	TUint hashBytes = hmac->HashSize();
    39 	TUint c = aIterations;
    40 	TUint l = aKey.Length() / hashBytes; 
    41 	if(aKey.Length() % hashBytes != 0) //round up if mod !=0
    42 		{
    43 		l+=1;
    44 		}
    45 	TUint r = aKey.Length() - (l-1) * hashBytes; //r == length of last block
    46 	
    47 	HBufC8* TiTemp = HBufC8::NewLC(hashBytes);
    48 	TUint32* Ti = (TUint32*)(TiTemp->Ptr());
    49 	aKey.SetLength(0); //we've already saved the length we want
    50 
    51 	HBufC8* STemp = HBufC8::NewLC(aSalt.Length() + sizeof(TUint32));
    52 	TUint32* S = (TUint32*)(STemp->Ptr());
    53 
    54 	HBufC8* UiTemp = HBufC8::NewLC(hashBytes);
    55 	TUint32* Ui = (TUint32*)(UiTemp->Ptr());
    56 
    57 	const TUint32* salt = (TUint32*)(aSalt.Ptr());
    58 	TUint saltBytes = aSalt.Length();
    59 
    60 	for(TUint i = 1; i<=l; i++)
    61 		{
    62 		F(*hmac, Ti, S, Ui, hashBytes, salt, saltBytes, c, i);
    63 		if(i == l)
    64 			aKey.Append((TUint8*)Ti, r);
    65 		else 
    66 			aKey.Append((TUint8*)Ti, hashBytes);
    67 		}
    68 
    69 	CleanupStack::PopAndDestroy(UiTemp);
    70 	CleanupStack::PopAndDestroy(STemp);
    71 	CleanupStack::PopAndDestroy(TiTemp);
    72 	CleanupStack::PopAndDestroy(hmac);
    73 	}
    74 
    75 void TPKCS5KDF::F(CMessageDigest& aDigest, TUint32* aAccumulator, 
    76 	TUint32* S, TUint32* Ui, TUint aHashBytes, const TUint32* aSalt, 
    77 	TUint aSaltBytes, TUint c, TUint i)
    78 	{
    79 	TUint8 itmp[4];
    80 	itmp[0] = (TUint8)((i >> 24) & 0xff);
    81 	itmp[1] = (TUint8)((i >> 16) & 0xff);
    82 	itmp[2] = (TUint8)((i >> 8) & 0xff);
    83 	itmp[3] = (TUint8)(i & 0xff);
    84 	TUint8* endOfS = Mem::Copy(S, aSalt, aSaltBytes);
    85 	Mem::Copy((TUint32*)endOfS, (TUint32*)&itmp, 4);
    86 
    87 	TPtr8 sptr((TUint8*)S, aSaltBytes+4);
    88 	sptr.SetLength(aSaltBytes+4);
    89 	Mem::Copy(aAccumulator, (TUint32*)((aDigest.Final(sptr)).Ptr()),aHashBytes);
    90 	Mem::Copy(Ui, aAccumulator, aHashBytes);
    91 
    92 	for(TUint j=1; j<c; j++)
    93 		{
    94 		TPtr8 uiptr((TUint8*)Ui, aHashBytes);
    95 		uiptr.SetLength(aHashBytes);
    96 		Mem::Copy(Ui, (TUint32*)((aDigest.Final(uiptr)).Ptr()), aHashBytes);
    97 		XORString(Ui, aAccumulator, aHashBytes);
    98 		}
    99 	}
   100 
   101 inline void TPKCS5KDF::XORString(const TUint32* aOp1, TUint32* aOp2,
   102 	TUint aLength)
   103 	{
   104 	const TUint32* i = aOp1;
   105 
   106 	//this will overflow the whole final word if aLength % 4 != 0 
   107 	//but I can't see this mattering cuz all memory allocation is on a word by word basis
   108 	//i don't want to do this byte by byte as it'll be way slower
   109 	//also, every sane digest is going to be a multiple of 4 -- so this isn't a problem
   110 	for( ; aOp1 != (TUint32*)((TUint8*)i + aLength); )
   111 		{
   112 			*aOp2++ ^= *aOp1++;	
   113 		}
   114 	}
   115