os/ossrv/genericopenlibs/cstdlib/TSTLIB/THELLOU.C
author sl
Tue, 10 Jun 2014 14:32:02 +0200
changeset 1 260cb5ec6c19
permissions -rw-r--r--
Update contrib.
     1 /*
     2 * Copyright (c) 1997-2009 Nokia Corporation and/or its subsidiary(-ies).
     3 * All rights reserved.
     4 * This component and the accompanying materials are made available
     5 * under the terms of "Eclipse Public License v1.0"
     6 * which accompanies this distribution, and is available
     7 * at the URL "http://www.eclipse.org/legal/epl-v10.html".
     8 *
     9 * Initial Contributors:
    10 * Nokia Corporation - initial contribution.
    11 *
    12 * Contributors:
    13 *
    14 * Description:
    15 * A variant of "Hello World" which reports various bits of its environment
    16 * and returns an interesting exit status
    17 * 
    18 *
    19 */
    20 
    21 
    22 
    23 #include <stdio.h>
    24 #include <stdlib.h>
    25 #include <unistd.h>
    26 #include <string.h>
    27 #include <sys/wait.h>
    28 #include "CTEST.H"
    29 
    30 #ifdef __WINS__
    31 int triangle_recurse(char* prog, char* num, int progress)
    32 	{
    33 	printf("\nBut not under WINS where I'll be told 0\n");
    34 	return 0;
    35 	}
    36 
    37 int triangle_parallel(char* prog, char* num)
    38 	{
    39 	printf("\nBut not under WINS where I'll be told 0\n");
    40 	return 0;
    41 	}
    42 
    43 #else
    44 
    45 int triangle_recurse(char* prog, char* num, int progress)
    46 	{
    47 	int n;
    48 	int pid, ret;
    49 	char cmd[100];
    50 	int fids[3];
    51 
    52 	n = atol(num);
    53 	if (n<1)
    54 		return 0;
    55 
    56 	sprintf(cmd, "%s do_triangle %d", prog, n-1);
    57 	if (progress)
    58 		{
    59 		pid=popen3(cmd, "", 0, fids);
    60 		if (pid<0)
    61 			{
    62 			fprintf(stderr, "Executing %s, ", cmd);
    63 			perror("popen3 failed");
    64 			return -1999999;
    65 			}
    66 		while (1)
    67 			{
    68 			int n=waitpid(pid, &ret, WNOHANG);
    69 			if (n==pid)
    70 				break;
    71 			printf(".");
    72 			fflush(stdout);
    73 			sleep(1);
    74 			}
    75 		}
    76 	else
    77 		ret=system(cmd);
    78 	return n+ret;
    79 	}
    80 
    81 int triangle_parallel(char* prog, char* num)
    82 	{
    83 	int n;
    84 	int pid, pid1, pid2, ret1, ret2, base, split;
    85 	char cmd[100];
    86 	int fids1[3], fids2[3];
    87 	char* basep;
    88 
    89 	n = atol(num);
    90 	if (n<1)
    91 		return 0;
    92 	basep=getenv("TRIANGLE_BASE");
    93 	if (basep==0)
    94 		return 0;
    95 	base=atol(basep);
    96 
    97 	/* we have to add up the numbers base..n inclusive
    98 	 */
    99 	if (base==n)
   100 		return n;
   101 	if (base+1==n)
   102 		return base+n;
   103 
   104 	/* At least 3 numbers, so split it into subtasks for child processes
   105 	 */
   106 	split = (n-base)/2;
   107 
   108 	sprintf(cmd, "%s do_trianglep %d", prog, base+split);
   109 	pid1=popen3(cmd, "", 0, fids1);
   110 	if (pid1<0)
   111 		{
   112 		fprintf(stderr, "Doing %d..%d of %d..%d", base+split, base, n, base);
   113 		perror("popen3 failed");
   114 		return -1999999;
   115 		}
   116 	
   117 	sprintf(cmd, "%d", base+split+1);
   118 	setenv("TRIANGLE_BASE", cmd, 1);
   119 
   120 	sprintf(cmd, "%s do_trianglep %d", prog, n);
   121 	pid2=popen3(cmd, "", 0, fids2);
   122 	if (pid2<0)
   123 		{
   124 		fprintf(stderr, "Doing %d..%d of %d..%d", n, base+split+1, n, base);
   125 		perror("popen3 failed");
   126 		return -1999999;
   127 		}
   128 	
   129 	/* Now collect the results */
   130 	ret1=-10000;
   131 	ret2=-10000;
   132 	for (n=0; n<2; n++)
   133 		{
   134 		int ret=-3999999;
   135 		pid=wait(&ret);
   136 		if (pid<0)
   137 			{
   138 			perror("waitpid failed");
   139 			return -2999999;
   140 			}
   141 		if (pid==pid1)
   142 			{
   143 			pid1=-1;
   144 			ret1=ret;
   145 			}
   146 		else if (pid==pid2)
   147 			{
   148 			pid2=-1;
   149 			ret2=ret;
   150 			}
   151 		else
   152 			printf("Unexpected pid %d (not %d or %d)\n", pid, pid1, pid2);
   153 		}
   154 	return ret1+ret2;
   155 	}
   156 
   157 #endif
   158 
   159 /**
   160 Usage:  THELLOU [triangle[p] <n>]
   161 
   162 @SYMTestCaseID          SYSLIB-STDLIB-CT-1058
   163 @SYMTestCaseDesc	    Tests for printing to standard output stream
   164 @SYMTestPriority 	    High
   165 @SYMTestActions  	    Prints some stuff (looks at args, getenv("USER"), cwd) to stdout and stderr.
   166 						Will compute triangle numbers by calling itself recursively, or parallel subdivison
   167 @SYMTestExpectedResults Test must not fail
   168 @SYMREQ                 REQ0000
   169 */		
   170 int main (int argc, char *argv[])
   171 	{
   172 	char *user=getenv("USER");
   173 	char cwd[MAXPATHLEN];
   174 	int ret=3, i;
   175 
   176 	start_redirection_server();
   177 	
   178 	if (argc==3 && strcmp(argv[1],"do_triangle")==0)
   179 		return triangle_recurse(argv[0], argv[2], 0);
   180 
   181 	if (argc==3 && strcmp(argv[1],"do_trianglep")==0)
   182 		return triangle_parallel(argv[0], argv[2]);
   183 
   184 	if (user)
   185 		{
   186 		printf("Hello %s\n", user);
   187 		ret=4;
   188 		}
   189 	else
   190 		printf("Greetings.\n");
   191 
   192 	printf("I am process %d\n", getpid());
   193 
   194 	if (getcwd(cwd,sizeof(cwd))!=0)
   195 		printf("I am speaking to you from %s\n", cwd);
   196 
   197 	printf("I have %d arguments: ", argc);
   198 	for (i=0; i<argc; i++)
   199 		printf(">%s< ", argv[i]);
   200 	printf("\r\n");
   201 
   202 	printf("In a few moments I shall say %c to stderr:\n", 'a'+argc);
   203 	fflush(stdout);
   204 
   205 	fprintf(stderr, "%c\n", 'a'+argc);
   206 	fflush(stderr);
   207 
   208 	if (argc==3 && strcmp(argv[1],"triangle")==0)
   209 		{
   210 		printf("For my next trick I shall compute the triangle of %s: ", argv[2]);
   211 		fflush(stdout);
   212 		ret=triangle_recurse(argv[0], argv[2], 1);
   213 		printf("it's %d\n", ret);
   214 		}
   215 
   216 	if (argc==3 && strcmp(argv[1],"trianglep")==0)
   217 		{
   218 		printf("I shall now compute the triangle of %s using a parallel algorithm: ", argv[2]);
   219 		fflush(stdout);
   220 		setenv("TRIANGLE_BASE", "1", 0);
   221 		ret=triangle_parallel(argv[0], argv[2]);
   222 		printf("it's %d\n", ret);
   223 		}
   224 
   225 	printf("Farewell...\nPress a key");
   226 	getchar();
   227 	return ret;
   228 	}