os/ossrv/ssl/libcrypto/src/crypto/bn/bn_recp.c
author sl
Tue, 10 Jun 2014 14:32:02 +0200
changeset 1 260cb5ec6c19
permissions -rw-r--r--
Update contrib.
sl@0
     1
/* crypto/bn/bn_recp.c */
sl@0
     2
/* Copyright (C) 1995-1998 Eric Young (eay@cryptsoft.com)
sl@0
     3
 * All rights reserved.
sl@0
     4
 *
sl@0
     5
 * This package is an SSL implementation written
sl@0
     6
 * by Eric Young (eay@cryptsoft.com).
sl@0
     7
 * The implementation was written so as to conform with Netscapes SSL.
sl@0
     8
 * 
sl@0
     9
 * This library is free for commercial and non-commercial use as long as
sl@0
    10
 * the following conditions are aheared to.  The following conditions
sl@0
    11
 * apply to all code found in this distribution, be it the RC4, RSA,
sl@0
    12
 * lhash, DES, etc., code; not just the SSL code.  The SSL documentation
sl@0
    13
 * included with this distribution is covered by the same copyright terms
sl@0
    14
 * except that the holder is Tim Hudson (tjh@cryptsoft.com).
sl@0
    15
 * 
sl@0
    16
 * Copyright remains Eric Young's, and as such any Copyright notices in
sl@0
    17
 * the code are not to be removed.
sl@0
    18
 * If this package is used in a product, Eric Young should be given attribution
sl@0
    19
 * as the author of the parts of the library used.
sl@0
    20
 * This can be in the form of a textual message at program startup or
sl@0
    21
 * in documentation (online or textual) provided with the package.
sl@0
    22
 * 
sl@0
    23
 * Redistribution and use in source and binary forms, with or without
sl@0
    24
 * modification, are permitted provided that the following conditions
sl@0
    25
 * are met:
sl@0
    26
 * 1. Redistributions of source code must retain the copyright
sl@0
    27
 *    notice, this list of conditions and the following disclaimer.
sl@0
    28
 * 2. Redistributions in binary form must reproduce the above copyright
sl@0
    29
 *    notice, this list of conditions and the following disclaimer in the
sl@0
    30
 *    documentation and/or other materials provided with the distribution.
sl@0
    31
 * 3. All advertising materials mentioning features or use of this software
sl@0
    32
 *    must display the following acknowledgement:
sl@0
    33
 *    "This product includes cryptographic software written by
sl@0
    34
 *     Eric Young (eay@cryptsoft.com)"
sl@0
    35
 *    The word 'cryptographic' can be left out if the rouines from the library
sl@0
    36
 *    being used are not cryptographic related :-).
sl@0
    37
 * 4. If you include any Windows specific code (or a derivative thereof) from 
sl@0
    38
 *    the apps directory (application code) you must include an acknowledgement:
sl@0
    39
 *    "This product includes software written by Tim Hudson (tjh@cryptsoft.com)"
sl@0
    40
 * 
sl@0
    41
 * THIS SOFTWARE IS PROVIDED BY ERIC YOUNG ``AS IS'' AND
sl@0
    42
 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
sl@0
    43
 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
sl@0
    44
 * ARE DISCLAIMED.  IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
sl@0
    45
 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
sl@0
    46
 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
sl@0
    47
 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
sl@0
    48
 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
sl@0
    49
 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
sl@0
    50
 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
sl@0
    51
 * SUCH DAMAGE.
sl@0
    52
 * 
sl@0
    53
 * The licence and distribution terms for any publically available version or
sl@0
    54
 * derivative of this code cannot be changed.  i.e. this code cannot simply be
sl@0
    55
 * copied and put under another distribution licence
sl@0
    56
 * [including the GNU Public Licence.]
sl@0
    57
 */
sl@0
    58
sl@0
    59
#include <stdio.h>
sl@0
    60
#include "cryptlib.h"
sl@0
    61
#include "bn_lcl.h"
sl@0
    62
sl@0
    63
EXPORT_C void BN_RECP_CTX_init(BN_RECP_CTX *recp)
sl@0
    64
	{
sl@0
    65
	BN_init(&(recp->N));
sl@0
    66
	BN_init(&(recp->Nr));
sl@0
    67
	recp->num_bits=0;
sl@0
    68
	recp->flags=0;
sl@0
    69
	}
sl@0
    70
sl@0
    71
EXPORT_C BN_RECP_CTX *BN_RECP_CTX_new(void)
sl@0
    72
	{
sl@0
    73
	BN_RECP_CTX *ret;
sl@0
    74
sl@0
    75
	if ((ret=(BN_RECP_CTX *)OPENSSL_malloc(sizeof(BN_RECP_CTX))) == NULL)
sl@0
    76
		return(NULL);
sl@0
    77
sl@0
    78
	BN_RECP_CTX_init(ret);
sl@0
    79
	ret->flags=BN_FLG_MALLOCED;
sl@0
    80
	return(ret);
sl@0
    81
	}
sl@0
    82
sl@0
    83
EXPORT_C void BN_RECP_CTX_free(BN_RECP_CTX *recp)
sl@0
    84
	{
sl@0
    85
	if(recp == NULL)
sl@0
    86
	    return;
sl@0
    87
sl@0
    88
	BN_free(&(recp->N));
sl@0
    89
	BN_free(&(recp->Nr));
sl@0
    90
	if (recp->flags & BN_FLG_MALLOCED)
sl@0
    91
		OPENSSL_free(recp);
sl@0
    92
	}
sl@0
    93
sl@0
    94
EXPORT_C int BN_RECP_CTX_set(BN_RECP_CTX *recp, const BIGNUM *d, BN_CTX *ctx)
sl@0
    95
	{
sl@0
    96
	if (!BN_copy(&(recp->N),d)) return 0;
sl@0
    97
	BN_zero(&(recp->Nr));
sl@0
    98
	recp->num_bits=BN_num_bits(d);
sl@0
    99
	recp->shift=0;
sl@0
   100
	return(1);
sl@0
   101
	}
sl@0
   102
sl@0
   103
EXPORT_C int BN_mod_mul_reciprocal(BIGNUM *r, const BIGNUM *x, const BIGNUM *y,
sl@0
   104
	BN_RECP_CTX *recp, BN_CTX *ctx)
sl@0
   105
	{
sl@0
   106
	int ret=0;
sl@0
   107
	BIGNUM *a;
sl@0
   108
	const BIGNUM *ca;
sl@0
   109
sl@0
   110
	BN_CTX_start(ctx);
sl@0
   111
	if ((a = BN_CTX_get(ctx)) == NULL) goto err;
sl@0
   112
	if (y != NULL)
sl@0
   113
		{
sl@0
   114
		if (x == y)
sl@0
   115
			{ if (!BN_sqr(a,x,ctx)) goto err; }
sl@0
   116
		else
sl@0
   117
			{ if (!BN_mul(a,x,y,ctx)) goto err; }
sl@0
   118
		ca = a;
sl@0
   119
		}
sl@0
   120
	else
sl@0
   121
		ca=x; /* Just do the mod */
sl@0
   122
sl@0
   123
	ret = BN_div_recp(NULL,r,ca,recp,ctx);
sl@0
   124
err:
sl@0
   125
	BN_CTX_end(ctx);
sl@0
   126
	bn_check_top(r);
sl@0
   127
	return(ret);
sl@0
   128
	}
sl@0
   129
sl@0
   130
EXPORT_C int BN_div_recp(BIGNUM *dv, BIGNUM *rem, const BIGNUM *m,
sl@0
   131
	BN_RECP_CTX *recp, BN_CTX *ctx)
sl@0
   132
	{
sl@0
   133
	int i,j,ret=0;
sl@0
   134
	BIGNUM *a,*b,*d,*r;
sl@0
   135
sl@0
   136
	BN_CTX_start(ctx);
sl@0
   137
	a=BN_CTX_get(ctx);
sl@0
   138
	b=BN_CTX_get(ctx);
sl@0
   139
	if (dv != NULL)
sl@0
   140
		d=dv;
sl@0
   141
	else
sl@0
   142
		d=BN_CTX_get(ctx);
sl@0
   143
	if (rem != NULL)
sl@0
   144
		r=rem;
sl@0
   145
	else
sl@0
   146
		r=BN_CTX_get(ctx);
sl@0
   147
	if (a == NULL || b == NULL || d == NULL || r == NULL) goto err;
sl@0
   148
sl@0
   149
	if (BN_ucmp(m,&(recp->N)) < 0)
sl@0
   150
		{
sl@0
   151
		BN_zero(d);
sl@0
   152
		if (!BN_copy(r,m)) return 0;
sl@0
   153
		BN_CTX_end(ctx);
sl@0
   154
		return(1);
sl@0
   155
		}
sl@0
   156
sl@0
   157
	/* We want the remainder
sl@0
   158
	 * Given input of ABCDEF / ab
sl@0
   159
	 * we need multiply ABCDEF by 3 digests of the reciprocal of ab
sl@0
   160
	 *
sl@0
   161
	 */
sl@0
   162
sl@0
   163
	/* i := max(BN_num_bits(m), 2*BN_num_bits(N)) */
sl@0
   164
	i=BN_num_bits(m);
sl@0
   165
	j=recp->num_bits<<1;
sl@0
   166
	if (j>i) i=j;
sl@0
   167
sl@0
   168
	/* Nr := round(2^i / N) */
sl@0
   169
	if (i != recp->shift)
sl@0
   170
		recp->shift=BN_reciprocal(&(recp->Nr),&(recp->N),
sl@0
   171
			i,ctx); /* BN_reciprocal returns i, or -1 for an error */
sl@0
   172
	if (recp->shift == -1) goto err;
sl@0
   173
sl@0
   174
	/* d := |round(round(m / 2^BN_num_bits(N)) * recp->Nr / 2^(i - BN_num_bits(N)))|
sl@0
   175
	 *    = |round(round(m / 2^BN_num_bits(N)) * round(2^i / N) / 2^(i - BN_num_bits(N)))|
sl@0
   176
	 *   <= |(m / 2^BN_num_bits(N)) * (2^i / N) * (2^BN_num_bits(N) / 2^i)|
sl@0
   177
	 *    = |m/N|
sl@0
   178
	 */
sl@0
   179
	if (!BN_rshift(a,m,recp->num_bits)) goto err;
sl@0
   180
	if (!BN_mul(b,a,&(recp->Nr),ctx)) goto err;
sl@0
   181
	if (!BN_rshift(d,b,i-recp->num_bits)) goto err;
sl@0
   182
	d->neg=0;
sl@0
   183
sl@0
   184
	if (!BN_mul(b,&(recp->N),d,ctx)) goto err;
sl@0
   185
	if (!BN_usub(r,m,b)) goto err;
sl@0
   186
	r->neg=0;
sl@0
   187
sl@0
   188
#if 1
sl@0
   189
	j=0;
sl@0
   190
	while (BN_ucmp(r,&(recp->N)) >= 0)
sl@0
   191
		{
sl@0
   192
		if (j++ > 2)
sl@0
   193
			{
sl@0
   194
			BNerr(BN_F_BN_DIV_RECP,BN_R_BAD_RECIPROCAL);
sl@0
   195
			goto err;
sl@0
   196
			}
sl@0
   197
		if (!BN_usub(r,r,&(recp->N))) goto err;
sl@0
   198
		if (!BN_add_word(d,1)) goto err;
sl@0
   199
		}
sl@0
   200
#endif
sl@0
   201
sl@0
   202
	r->neg=BN_is_zero(r)?0:m->neg;
sl@0
   203
	d->neg=m->neg^recp->N.neg;
sl@0
   204
	ret=1;
sl@0
   205
err:
sl@0
   206
	BN_CTX_end(ctx);
sl@0
   207
	bn_check_top(dv);
sl@0
   208
	bn_check_top(rem);
sl@0
   209
	return(ret);
sl@0
   210
	} 
sl@0
   211
sl@0
   212
/* len is the expected size of the result
sl@0
   213
 * We actually calculate with an extra word of precision, so
sl@0
   214
 * we can do faster division if the remainder is not required.
sl@0
   215
 */
sl@0
   216
/* r := 2^len / m */
sl@0
   217
EXPORT_C int BN_reciprocal(BIGNUM *r, const BIGNUM *m, int len, BN_CTX *ctx)
sl@0
   218
	{
sl@0
   219
	int ret= -1;
sl@0
   220
	BIGNUM *t;
sl@0
   221
sl@0
   222
	BN_CTX_start(ctx);
sl@0
   223
	if((t = BN_CTX_get(ctx)) == NULL) goto err;
sl@0
   224
sl@0
   225
	if (!BN_set_bit(t,len)) goto err;
sl@0
   226
sl@0
   227
	if (!BN_div(r,NULL,t,m,ctx)) goto err;
sl@0
   228
sl@0
   229
	ret=len;
sl@0
   230
err:
sl@0
   231
	bn_check_top(r);
sl@0
   232
	BN_CTX_end(ctx);
sl@0
   233
	return(ret);
sl@0
   234
	}